El peligro de los refranes españoles.
- Who gets up early, God helps.
- No matter how early dawn early.
- God can do early dawn.
I have a slight feeling of having seen this somewhere before but can not remember exactly.
Thursday, February 25, 2010
Red Burton Blunt Snowboard
Burdo
El peligro de los refranes españoles.
I have a slight feeling of having seen this somewhere before but can not remember exactly.
El peligro de los refranes españoles.
I have a slight feeling of having seen this somewhere before but can not remember exactly.
Thursday, February 11, 2010
Thick Gel Cervical Mucus Before Period
Five pirates, many coconuts and a monkey
Here is my humble contribution to I Math Carnival organized by Eliatron: a problem earlier this year by my math teacher. Do not collect any great difficulty because I'm only in 1 º Bachillerato.
A group of 5 pirates shipwrecked on an island full of coconuts in the who lives only a monkey. After much thought on how to survive, choose to gather all the coconuts on the island and pile. After a hard day's work, get collect them all and decide to leave the stack intact to pass on to the next morning.
But none of the pirates is wary of others. A first pirate gets up in the middle of the night, divides the lot into 5 parts and get a . But to divide the lot into 5 parts on a coconut, so it gives the mono . Soon after, another pirate gets up and returns to divide the lot into 5 parts and takes one, all without noticing the decline of the heap initial. Again on a coconut to make the 5 groups, so it also gave the monkey. As expected, stands another third pirate and repeat. Have divided the lot into 5 parts again on another coconut. "Who do I give? Then the monkey. "The fourth pirate gets up to divide the pile of coconuts into 5 parts, and stays with it. Decides to give the monkey a coconut that was left to the 5 sub-lots. And finally, we find the fifth and last pirate. Divide the pile into 5 parts, gives the leftover coconut mono and stays on your part.
arrives the next morning and split the current bunch of coconuts into 5 parts on either without . How many coconuts were in the first lot and many are left in the morning?
The problem posed by the teacher had here. I thought maybe the number of coconuts that had each pirate could follow a final order, and so is (but obviously depends on what value is taken as the first term of the sequence). 
Here is my humble contribution to I Math Carnival organized by Eliatron: a problem earlier this year by my math teacher. Do not collect any great difficulty because I'm only in 1 º Bachillerato.
A group of 5 pirates shipwrecked on an island full of coconuts in the who lives only a monkey. After much thought on how to survive, choose to gather all the coconuts on the island and pile. After a hard day's work, get collect them all and decide to leave the stack intact to pass on to the next morning.
But none of the pirates is wary of others. A first pirate gets up in the middle of the night, divides the lot into 5 parts and get a . But to divide the lot into 5 parts on a coconut, so it gives the mono . Soon after, another pirate gets up and returns to divide the lot into 5 parts and takes one, all without noticing the decline of the heap initial. Again on a coconut to make the 5 groups, so it also gave the monkey. As expected, stands another third pirate and repeat. Have divided the lot into 5 parts again on another coconut. "Who do I give? Then the monkey. "The fourth pirate gets up to divide the pile of coconuts into 5 parts, and stays with it. Decides to give the monkey a coconut that was left to the 5 sub-lots. And finally, we find the fifth and last pirate. Divide the pile into 5 parts, gives the leftover coconut mono and stays on your part.
arrives the next morning and split the current bunch of coconuts into 5 parts on either without . How many coconuts were in the first lot and many are left in the morning?
The problem posed by the teacher had here. I thought maybe the number of coconuts that had each pirate could follow a final order, and so is (but obviously depends on what value is taken as the first term of the sequence).
Saturday, February 6, 2010
Answers To The Ap Biology Lab 8
Mathematical Curiosities
2 ^ 0 +2 ^ 1 +2 ^ 2 +2 ^ 3 +2 ^ 4 +2 ^ 5 = (2 ^ 6) -1
2 ^ 0 +2 ^ 1 +...+ 2 ^ (x-1) = (2 ^ x) -1
2 • (3 ^ 0 +3 ^ 1 +3 ^ 2 +3 ^ 3 +3 ^ 4 +3 ^ 5) = (3 ^ 6) -1
2 • [3 ^ 0 +3 ^ 1 +...+ 3 ^ (x-1)] = (3 ^ x) -1
3 · (4 ^ 0 +4 ^ 1 +4 ^ 2 +4 ^ 3 +4 ^ 4 +4 ^ 5) = (4 ^ 6) -1
3 · [4 ^ 0 +4 ^ 1 +...+ 4 ^ (x-1)] = (4 ^ x) -1
[...]
11 • (12 ^ 0 +12 ^ 1 +12 ^ 2 +12 ^ 3 +12 ^ 4 +12 ^ 5) = (12 ^ 6) -1
11 • [12 ^ 0 +12 ^ 1 +. +12 .. ^ (x-1)] = (12 ^ x) -1
Conclusion
(y-1) · [y ^ y ^ 0 + 1 + y ^ 2 + .. . + and • (x-1)] = (y ^ x) -1
PS: I just discovered that this is related to the sum of geometric progressions, which I have not given yet. 
2 ^ 0 +2 ^ 1 +2 ^ 2 +2 ^ 3 +2 ^ 4 +2 ^ 5 = (2 ^ 6) -1
2 ^ 0 +2 ^ 1 +...+ 2 ^ (x-1) = (2 ^ x) -1
2 • (3 ^ 0 +3 ^ 1 +3 ^ 2 +3 ^ 3 +3 ^ 4 +3 ^ 5) = (3 ^ 6) -1
2 • [3 ^ 0 +3 ^ 1 +...+ 3 ^ (x-1)] = (3 ^ x) -1
3 · (4 ^ 0 +4 ^ 1 +4 ^ 2 +4 ^ 3 +4 ^ 4 +4 ^ 5) = (4 ^ 6) -1
3 · [4 ^ 0 +4 ^ 1 +...+ 4 ^ (x-1)] = (4 ^ x) -1
[...]
11 • (12 ^ 0 +12 ^ 1 +12 ^ 2 +12 ^ 3 +12 ^ 4 +12 ^ 5) = (12 ^ 6) -1
11 • [12 ^ 0 +12 ^ 1 +. +12 .. ^ (x-1)] = (12 ^ x) -1
Conclusion
(y-1) · [y ^ y ^ 0 + 1 + y ^ 2 + .. . + and • (x-1)] = (y ^ x) -1
PS: I just discovered that this is related to the sum of geometric progressions, which I have not given yet.
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